Question

(b) let x be the length of the hypotenuse. use 2² + 5² = x² (c) find x, the length of the hypotenuse. give an x =

Explanation:

Step1: Calculate the sum of squares

$2^{2}+5^{2}=4 + 25=29$
So, $x^{2}=29$.

Step2: Solve for x

Since $x^{2}=29$ and $x>0$ (as it represents the length of a side), then $x = \sqrt{29}$.

Answer:

$\sqrt{29}$