Question

a lightbulb has a resistance of 240 ω. if it is connected to a 120 v outlet, how much current is flowing through the bulb? $i = v/r$ 28,800a 2.0a 0.5a 1.5a an electric heater draws 15a of current when its internal resistance is 8ω. what is the voltage of the power source? $v = i r$ 23v 1.875v 120v 0.53v

Explanation:

Step1: Identify given values (bulb)

Resistance $R=240\ \Omega$, Voltage $V=120\ \text{V}$

Step2: Apply Ohm's Law ($I=V/R$)

$I=\frac{120}{240}=0.5\ \text{A}$

Step3: Identify given values (heater)

Current $I=15\ \text{A}$, Resistance $R=8\ \Omega$

Step4: Apply Ohm's Law ($V=IR$)

$V=15\times8=120\ \text{V}$

Answer:

1. 0.5A
2. 120V