Question

at a local college, 356 of the male students are smokers and 534 are non - smokers. of the female students, 200 are smokers and 800 are non - smokers. a male student and a female student from the college are randomly selected for a survey. what is the probability that both are smokers? do not round your answer. (if necessary, consult a list of formulas.)

Explanation:

Step1: Calculate total male students

$356 + 534 = 890$

Step2: Calculate total female students

$200 + 800 = 1000$

Step3: Find P(male smoker)

$\frac{356}{890}$

Step4: Find P(female smoker)

$\frac{200}{1000} = \frac{1}{5}$

Step5: Multiply the two probabilities

$\frac{356}{890} \times \frac{200}{1000} = \frac{356 \times 200}{890 \times 1000} = \frac{71200}{890000} = \frac{356}{4450} = \frac{178}{2225}$

Answer:

$\frac{178}{2225}$