Question

a log is either oak or pine. it displaces 2.7 gal of water and weighs 13.8 lb.
part a
calculate the density of the log in g/cm³.
express your answer using two significant figures.
0.88 g/cm³
previous answers
all attempts used; correct answer withheld by instructor
the correct answer does not depend on: cm.
part b
is the log oak or pine? (density of oak = 0.9 g/cm³; density of pine = 0.4 g/cm³)
the log is oak because the calculated density aligns with the density of oak
the log is pine because the calculated density aligns with the density of pine
the log is neither density nor pine because the calculated density does not align with the density of either type

Explanation:

Step1: Convert volume units

1 gal = 3785.41 cm³, so 2.7 gal = 2.7×3785.41 = 10220.607 cm³.

Step2: Convert mass units

1 lb = 453.592 g, so 13.8 lb = 13.8×453.592 = 6259.57 g.

Step3: Calculate density

Density $
ho=\frac{m}{V}$, where $m$ is mass and $V$ is volume. $
ho=\frac{6259.57}{10220.607}\approx0.61$ g/cm³ (rounded to two - significant figures).

For Part B:
Since the density of oak is 0.9 g/cm³ and the density of pine is 0.4 g/cm³, and the calculated density of the log is approximately 0.61 g/cm³, the log is neither oak nor pine because the calculated density does not align with the density of either type.

Answer:

Part A: $0.61$ g/cm³
Part B: The log is neither oak nor pine because the calculated density does not align with the density of either type.