QUESTION IMAGE
Question
look at this diagram: if bd and eg are parallel lines and m∠gfc = 115°, what is m∠bcf?
Step1: Recall linear - pair property
Linear - pair angles are supplementary, meaning they add up to 180°. ∠GFC and ∠BCF are a linear - pair of angles.
Let \(m\angle GFC = 115^{\circ}\) and \(m\angle BCF=x\).
We know that \(m\angle GFC + m\angle BCF=180^{\circ}\).
Step2: Solve for \(m\angle BCF\)
Substitute the value of \(m\angle GFC\) into the equation:
\(115^{\circ}+x = 180^{\circ}\)
\(x=180^{\circ}- 115^{\circ}\)
\(x = 65^{\circ}\)
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\(65^{\circ}\)