Question

m-f 8:30 - 9:20 college algebra with review
homework 2 and midpoint circles
question 9, 2.8.25
points: 0 of 1
find the midpoint of the line segment with endpoints (-5/3, 2/3) and (-13/3, -8/3).
the midpoint of the line segment is . (type an ordered pair, using integers or fractions.)

Explanation:

Step1: Recall mid - point formula

The mid - point formula for two points $(x_1,y_1)$ and $(x_2,y_2)$ is $(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$. Here $x_1=-\frac{5}{3}$, $y_1=\frac{2}{3}$, $x_2 =-\frac{13}{3}$, $y_2=-\frac{8}{3}$.

Step2: Calculate the x - coordinate of the mid - point

$x=\frac{-\frac{5}{3}+(-\frac{13}{3})}{2}=\frac{-\frac{5 + 13}{3}}{2}=\frac{-\frac{18}{3}}{2}=\frac{- 6}{2}=-3$.

Step3: Calculate the y - coordinate of the mid - point

$y=\frac{\frac{2}{3}+(-\frac{8}{3})}{2}=\frac{\frac{2-8}{3}}{2}=\frac{-\frac{6}{3}}{2}=\frac{-2}{2}=-1$.

Answer:

$(-3,-1)$