Question

1. make a punnett square for a cross between two dog parents with semi - floppy ears (ee). fill in the genotypes and phenotypes for all the possible offspring. (tip: see question 5 for more information about these alleles)

f. calculating probability
dominant, recessive, and co - dominant traits follow predictable inheritance patterns. you can use a punnett square to predict the chances (or probability) of offspring having each possible genotype and phenotype.
example
this punnett square has 4 squares, which together represent all the possible genotypes for offspring from this cross. so for each possibility, the probability is ¼, or 25%. together, the possibilities add up to 1 (¼ + ¼ + ¼ + ¼), or 100% (25% + 25% + 25% + 25%)
in the punnett square above, two squares have a tt genotype, which makes a tall phenotype. to calculate the probability of this combination, you can add the values of the squares.
probability of tall phenotype (t_)
25% + 25% = 50% (or) ¼ + ¼ = ½
you can do the same for the short phenotype (tt)
25% + 25% = 50% (or) ¼ + ¼ = ½
these calculations tell us that if these two parents make an offspring, there is a 50% (or 1 in 2) chance that it will be tall, and a 50% (or 1 in 2) chance that it will be short.

Explanation:

Answer:

1. Punnett square for $E^F e^f \times E^F e^f$:

	$E^F$	$e^f$
$e^f$	$E^F e^f$	$e^f e^f$

Genotypes: $25\% E^F E^F$, $50\% E^F e^f$, $25\% e^f e^f$