Question

many ways you could solve this equation. we need to get v alone on orber alone on the other side. since v is inside the parentheses on the le property to rewrite the equation without parentheses. go for it. dis12v - 8. you can think of this as (12v - 8) is being multiplied by \\(\frac{1}{2}\\). \\(\frac{1}{2}(12v - 8) = 8v + 10\\) \\(square = 8v + 10\\)

Explanation:

Step1: Apply distributive property

We use the distributive property \( \frac{1}{2}(a - b)=\frac{1}{2}a-\frac{1}{2}b \) to expand \( \frac{1}{2}(12v - 8) \).
\( \frac{1}{2}\times12v-\frac{1}{2}\times8 \)

Step2: Calculate each term

Calculate \( \frac{1}{2}\times12v = 6v \) and \( \frac{1}{2}\times8 = 4 \), so the left - hand side becomes \( 6v-4 \).

Answer:

\( 6v - 4 \)