Question

1. a map has a scale of 2 in : 6 mi. if clayton and centerville are 10 in apart on the map then how far apart are the real cities?

Explanation:

Step1: Set up proportion

Let $x$ be the real - distance. The proportion is $\frac{2}{6}=\frac{10}{x}$.

Step2: Cross - multiply

$2x = 6\times10$.

Step3: Solve for $x$

$2x=60$, so $x = 30$.

Answer:

30 mi