Question

1. mariana fed 1/6 of a box of crackers to the birds outside her house. she shared the rest with nina.

select all the ways they could have shared the remaining crackers.
○ mariana ate 2/6; nina ate 4/6.
○ mariana at 3/6; nina ate 2/6.
○ mariana at 4/6; nina ate 1/6.
○ mariana at 1/6; nina ate 2/6.
○ mariana at 3/6; nina ate 3/6.

Explanation:

Step1: Find the remaining crackers

The total is considered as 1 (or $\frac{6}{6}$). Mariana fed $\frac{1}{6}$ to the birds, so the remaining is $1 - \frac{1}{6}=\frac{6 - 1}{6}=\frac{5}{6}$.

Step2: Check each option

• Option 1: Mariana ate $\frac{2}{6}$, Nina ate $\frac{4}{6}$. Sum: $\frac{2}{6}+\frac{4}{6}=\frac{6}{6}

eq\frac{5}{6}$. Incorrect.

• Option 2: Mariana at $\frac{3}{6}$, Nina ate $\frac{2}{6}$. Sum: $\frac{3}{6}+\frac{2}{6}=\frac{5}{6}$. Correct.
• Option 3: Mariana at $\frac{4}{6}$, Nina ate $\frac{1}{6}$. Sum: $\frac{4}{6}+\frac{1}{6}=\frac{5}{6}$. Correct.
• Option 4: Mariana at $\frac{1}{6}$, Nina ate $\frac{2}{6}$. Sum: $\frac{1}{6}+\frac{2}{6}=\frac{3}{6}

eq\frac{5}{6}$. Incorrect.

• Option 5: Mariana at $\frac{3}{6}$, Nina ate $\frac{3}{6}$. Sum: $\frac{3}{6}+\frac{3}{6}=\frac{6}{6}

eq\frac{5}{6}$. Incorrect.

Answer:

B. Mariana at $\frac{3}{6}$; Nina ate $\frac{2}{6}$, C. Mariana at $\frac{4}{6}$; Nina ate $\frac{1}{6}$