Question

1. what is $(3v - 3)(4v - 2)?$

a. $12v^{2}-20v + 5$
b. $12v^{2}-16v + 6$
c. $12v^{2}-18v + 8$
d. $12v^{2}-18v + 6$

Explanation:

Step1: Apply FOIL method

First terms: $3v \times 4v = 12v^2$
Outer terms: $3v \times (-2) = -6v$
Inner terms: $-3 \times 4v = -12v$
Last terms: $-3 \times (-2) = 6$

Step2: Combine like terms

$12v^2 + (-6v -12v) + 6 = 12v^2 -16v +6$

Answer:

b. $12v^2 - 16v + 6$