Question

1. \\(\frac{1}{y^{9}} cdot y^{15}\\)

Explanation:

Step1: Rewrite as negative exponent

$\frac{1}{y^9} = y^{-9}$

Step2: Apply exponent product rule

$y^{-9} \cdot y^{15} = y^{-9+15}$

Step3: Simplify the exponent

$y^{-9+15} = y^{6}$

Answer:

$y^6$