Question

16.
$-1 \begin{bmatrix} 6 & -3 \\ 0 & 2 end{bmatrix} - 3 \begin{bmatrix} -4 & 1 \\ 5 & -1 end{bmatrix}$

Explanation:

Step1: Multiply matrices by scalars

First matrix: $-1 \times

$$\begin{bmatrix} 6 & -3 \\ 0 & 2 \end{bmatrix}$$

=

$$\begin{bmatrix} -6 & 3 \\ 0 & -2 \end{bmatrix}$$

$
Second matrix: $-3 \times

$$\begin{bmatrix} -4 & 1 \\ 5 & -1 \end{bmatrix}$$

=

$$\begin{bmatrix} 12 & -3 \\ -15 & 3 \end{bmatrix}$$

$

Step2: Add resulting matrices

Add corresponding elements:

$$\begin{bmatrix} -6+12 & 3+(-3) \\ 0+(-15) & -2+3 \end{bmatrix}$$

Answer:

$$\begin{bmatrix} 6 & 0 \\ -15 & 1 \end{bmatrix}$$