Question

1. $12a^{3}+4a^{2}+3ab + b$

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms:
$$(12a^{3}+4a^{2})+(3ab + b)$$

Step2: Factor out the GCF from each group

Factor out \(4a^{2}\) from the first group and \(b\) from the second group:
$$4a^{2}(3a + 1)+b(3a + 1)$$

Step3: Factor out the common binomial factor

Factor out \((3a + 1)\) from both terms:
$$(3a + 1)(4a^{2}+b)$$

Answer:

\((3a + 1)(4a^{2}+b)\)