Question

1. $x^3 + 2x^2 - 8x - 16$

Explanation:

Step1: Group terms for factoring

$(x^3 + 2x^2) + (-8x - 16)$

Step2: Factor out GCF from each group

$x^2(x + 2) - 8(x + 2)$

Step3: Factor out common binomial

$(x + 2)(x^2 - 8)$

Step4: Factor difference of squares (optional)

$(x + 2)(x - 2\sqrt{2})(x + 2\sqrt{2})$

Answer:

$(x + 2)(x^2 - 8)$ or $(x + 2)(x - 2\sqrt{2})(x + 2\sqrt{2})$