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Question
- $8a^{8} cdot -6a^{10}$
Step1: Multiply the coefficients
Multiply 8 and -6: \(8\times(-6)= -48\)
Step2: Multiply the variables using exponent rule
For \(a^8 \cdot a^{10}\), use \(a^m \cdot a^n = a^{m + n}\), so \(a^8 \cdot a^{10}=a^{8 + 10}=a^{18}\)
Step3: Combine the results
Multiply the coefficient result and the variable result: \(-48\times a^{18}=-48a^{18}\)
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\(-48a^{18}\)