Question

1. $sqrt3{-250x^{6}y^{5}}$

Explanation:

Step1: Factor the coefficient

$-250 = -5^3 \times 2$

Step2: Simplify variables

$x^6 = (x^2)^3$, $y^5 = y^3 \times y^2$

Step3: Combine and simplify cube root

$\sqrt[3]{-5^3(x^2)^3y^3 \cdot 2y^2} = -5x^2y\sqrt[3]{2y^2}$

Answer:

$-5x^2y\sqrt[3]{2y^2}$