Question

(2x^5 + y^5)^2

Explanation:

Step1: Recall the square of a binomial formula

The formula for squaring a binomial \((a + b)^2\) is \(a^2 + 2ab + b^2\). Here, \(a = 2x^5\) and \(b = y^5\).

Step2: Calculate \(a^2\)

\(a^2=(2x^5)^2 = 2^2\times(x^5)^2=4x^{10}\)

Step3: Calculate \(2ab\)

\(2ab = 2\times(2x^5)\times(y^5)=4x^5y^5\)

Step4: Calculate \(b^2\)

\(b^2=(y^5)^2 = y^{10}\)

Step5: Combine the terms

\((2x^5 + y^5)^2=4x^{10}+4x^5y^5 + y^{10}\)

Answer:

\(4x^{10}+4x^5y^5 + y^{10}\)