Question

1. $3b^{-3} \cdot 2b^{-2}$

Explanation:

Step1: Multiply the coefficients

$3 \times 2 = 6$

Step2: Combine like variables via exponent rule

$b^{-3} \cdot b^{-2} = b^{-3 + (-2)} = b^{-5}$

Step3: Rewrite negative exponent as reciprocal

$b^{-5} = \frac{1}{b^5}$

Step4: Combine coefficient and variable term

$6 \times \frac{1}{b^5} = \frac{6}{b^5}$

Answer:

$\frac{6}{b^5}$