Question

1. evaluate: \\(dfrac{3x - y}{6z - x}\\) if \\(x = 2, y = 8,\\) and \\(z = -2\\). a) \\(dfrac{1}{7}\\) b) \\(-dfrac{1}{7}\\) c) \\(dfrac{1}{5}\\) d) \\(-dfrac{1}{5}\\)

Explanation:

Step1: Substitute values into numerator

$3(2) - 8 = 6 - 8 = -2$

Step2: Substitute values into denominator

$6(-2) - 2 = -12 - 2 = -14$

Step3: Simplify the fraction

$\frac{-2}{-14} = \frac{1}{7}$

Answer:

A) $\frac{1}{7}$