Question

$4x + 6y + 5z = 70$
$4x + 6y = 60$
$3x = 18$

Explanation:

Step1: Solve for $x$

Divide both sides by 3:
$$x = \frac{18}{3} = 6$$

Step2: Substitute $x$ to find $y$

Plug $x=6$ into $4x+6y=60$:
$$4(6) + 6y = 60$$
$$24 + 6y = 60$$
Subtract 24 from both sides:
$$6y = 60 - 24 = 36$$
Divide by 6:
$$y = \frac{36}{6} = 6$$

Step3: Substitute $x,y$ to find $z$

Plug $x=6,y=6$ into $4x+6y+5z=70$:
$$4(6) + 6(6) + 5z = 70$$
$$24 + 36 + 5z = 70$$
$$60 + 5z = 70$$
Subtract 60 from both sides:
$$5z = 70 - 60 = 10$$
Divide by 5:
$$z = \frac{10}{5} = 2$$

Answer:

$x=6$, $y=6$, $z=2$