Question

1. multiply $-3x^{2}y(4yx^{4}+2xy^{2}-5y^{2}x^{3}).LXB0\bigcirc -12x^{6}y^{2}-6x^{3}y^{3}+15x^{5}y^{3}LXB1\bigcirc -3x^{8}y^{2}$

Explanation:

Step1: Distribute the monomial

$-3x^2y \times 4yx^4 + (-3x^2y) \times 2xy^2 + (-3x^2y) \times (-5y^2x^3)$

Step2: Multiply terms (combine exponents)

For the first term: $-3 \times 4 \times x^{2+4} \times y^{1+1} = -12x^6y^2$
For the second term: $-3 \times 2 \times x^{2+1} \times y^{1+2} = -6x^3y^3$
For the third term: $-3 \times (-5) \times x^{2+3} \times y^{1+2} = 15x^5y^3$

Step3: Combine all terms

$-12x^6y^2 - 6x^3y^3 + 15x^5y^3$

Answer:

$\boldsymbol{-12x^6y^2 - 6x^3y^3 + 15x^5y^3}$ (matches the first option)