Question

1. \\(\sqrt4{x^8 y^{12}}\\)

Explanation:

Step1: Rewrite root as exponent

$\sqrt[4]{x^8 y^{12}} = (x^8 y^{12})^{\frac{1}{4}}$

Step2: Distribute exponent to each term

$(x^8)^{\frac{1}{4}} \cdot (y^{12})^{\frac{1}{4}}$

Step3: Simplify exponents

$x^{8 \times \frac{1}{4}} \cdot y^{12 \times \frac{1}{4}} = x^2 y^3$

Answer:

$x^2 y^3$