Question

1. $y = 2(x + 3)^2 - 4$ vertex

$a = $

Explanation:

Step1: Identify vertex form

The vertex form of a quadratic function is $y = a(x - h)^2 + k$, where $(h,k)$ is the vertex, and $a$ is the leading coefficient.

Step2: Match to given function

Given $y = 2(x + 3)^2 - 4$, rewrite as $y = 2(x - (-3))^2 + (-4)$. Here, $h=-3$, $k=-4$, $a=2$.

Step3: State vertex and $a$

Vertex is $(h,k) = (-3, -4)$, $a=2$.

Answer:

Vertex: $(-3, -4)$
$a = 2$