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Question
- $x^{-4}y^{2}cdot (x^{-2}y^{-2})^{2}$
Step1: Apply power of a product rule
$(x^{-2}y^{-2})^2 = x^{-2\times2}y^{-2\times2} = x^{-4}y^{-4}$
Step2: Multiply like terms with exponents
$x^{-4}y^{2} \cdot x^{-4}y^{-4} = x^{-4+(-4)}y^{2+(-4)}$
Step3: Simplify the exponents
$x^{-8}y^{-2} = \frac{1}{x^8y^2}$
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$\frac{1}{x^8y^2}$