Question

1. $y = - (x - 1)^2$ vertex: ___________

a = ___________

Explanation:

Step1: Identify vertex form

The vertex form of a quadratic function is $y = a(x - h)^2 + k$, where $(h,k)$ is the vertex.

Step2: Match to given function

For $y = -(x - 1)^2$, this is equivalent to $y = -1(x - 1)^2 + 0$. Here, $h=1$, $k=0$, and $a=-1$.

Step3: Determine vertex

The vertex $(h,k)$ is $(1, 0)$.

Answer:

Vertex: $(1, 0)$
$a = -1$