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Question
- $3\frac{3}{8}-\frac{8}{12}=$ __________ 8. $40\frac{1}{5}-10\frac{5}{10}=$ ________ 9. $\frac{5}{12}+1\frac{5}{8}+4\frac{3}{6}=$ ________ 10. $20 - (\frac{3}{9}+2\frac{1}{6})=$ __________
Step1: Convert mixed - numbers to improper fractions for 7
$3\frac{3}{8}=\frac{3\times8 + 3}{8}=\frac{27}{8}$
Step2: Find a common denominator for 7
The common denominator of 8 and 12 is 24. $\frac{27}{8}=\frac{27\times3}{8\times3}=\frac{81}{24}$, $\frac{8}{12}=\frac{8\times2}{12\times2}=\frac{16}{24}$
Step3: Subtract the fractions for 7
$\frac{81}{24}-\frac{16}{24}=\frac{81 - 16}{24}=\frac{65}{24}=2\frac{17}{24}$
Step4: Convert mixed - numbers to improper fractions for 8
$40\frac{1}{5}=\frac{40\times5+1}{5}=\frac{201}{5}$, $10\frac{5}{10}=\frac{10\times10 + 5}{10}=\frac{105}{10}=\frac{21}{2}$
Step5: Find a common denominator for 8
The common denominator of 5 and 2 is 10. $\frac{201}{5}=\frac{201\times2}{5\times2}=\frac{402}{10}$, $\frac{21}{2}=\frac{21\times5}{2\times5}=\frac{105}{10}$
Step6: Subtract the fractions for 8
$\frac{402}{10}-\frac{105}{10}=\frac{402 - 105}{10}=\frac{297}{10}=29\frac{7}{10}$
Step7: Convert mixed - numbers to improper fractions for 9
$1\frac{5}{8}=\frac{1\times8 + 5}{8}=\frac{13}{8}$, $4\frac{3}{6}=\frac{4\times6+3}{6}=\frac{27}{6}=\frac{9}{2}$
The common denominator of 12, 8 and 2 is 24. $\frac{5}{12}=\frac{5\times2}{12\times2}=\frac{10}{24}$, $\frac{13}{8}=\frac{13\times3}{8\times3}=\frac{39}{24}$, $\frac{9}{2}=\frac{9\times12}{2\times12}=\frac{108}{24}$
$\frac{10}{24}+\frac{39}{24}+\frac{108}{24}=\frac{10 + 39+108}{24}=\frac{157}{24}=6\frac{13}{24}$
Step8: Convert mixed - numbers to improper fractions for 10
$2\frac{1}{6}=\frac{2\times6 + 1}{6}=\frac{13}{6}$, $\frac{3}{9}=\frac{1}{3}$
The common denominator of 3 and 6 is 6. $\frac{1}{3}=\frac{1\times2}{3\times2}=\frac{2}{6}$
$\frac{3}{9}+2\frac{1}{6}=\frac{2}{6}+\frac{13}{6}=\frac{2 + 13}{6}=\frac{15}{6}=\frac{5}{2}$
$20-\frac{5}{2}=\frac{20\times2}{1\times2}-\frac{5}{2}=\frac{40 - 5}{2}=\frac{35}{2}=17\frac{1}{2}$
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