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8) $f(x) = -|x + 5| + 1$; find $f(-8)$ $f(-8) = -|-8 + 5| + 1$

Question

  1. $f(x) = -|x + 5| + 1$; find $f(-8)$

$f(-8) = -|-8 + 5| + 1$

Explanation:

Step1: Substitute $x=-8$ into $f(x)$

$f(-8) = -|-8 + 5| + 1$

Step2: Simplify inside absolute value

$-8 + 5 = -3$, so $f(-8) = -|-3| + 1$

Step3: Evaluate absolute value

$|-3| = 3$, so $f(-8) = -3 + 1$

Step4: Calculate final sum

$-3 + 1 = -2$

Answer:

$-2$