Question

$9^{x-4}=3^{x+3}$
1 out of 2

Explanation:

Step1: Rewrite base to match

$9^{x-4} = (3^2)^{x-4} = 3^{2(x-4)}$

Step2: Set exponents equal

Since bases are equal, $2(x-4) = x+3$

Step3: Expand left side

$2x - 8 = x + 3$

Step4: Isolate x term

$2x - x = 3 + 8$

Step5: Calculate final value

$x = 11$

Answer:

$x=11$