Question

add.
$(6b^{2}-3b - 4)+(4b^{2}+2b - 4)$

Explanation:

Step1: Remove parentheses

To add the two polynomials, we first remove the parentheses. Since there is a plus sign in front of both parentheses, the signs of the terms inside remain the same. So we have:
\(6b^{2}-3b - 4+4b^{2}+2b - 4\)

Step2: Combine like terms

Next, we combine the like terms. For the \(b^{2}\) terms: \(6b^{2}+4b^{2}=10b^{2}\). For the \(b\) terms: \(-3b + 2b=-b\). For the constant terms: \(-4-4 = -8\).

Putting it all together, we get:
\(10b^{2}-b - 8\)

Answer:

\(10b^{2}-b - 8\)