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Question
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$$\begin{cases} y - 4x = 0 \\\\ x + y = 5 \\end{cases}$$
Step1: Express y from first equation
From \( y - 4x = 0 \), we get \( y = 4x \).
Step2: Substitute y into second equation
Substitute \( y = 4x \) into \( x + y = 5 \), we have \( x + 4x = 5 \).
Step3: Solve for x
Simplify \( x + 4x = 5 \) to \( 5x = 5 \), then \( x = \frac{5}{5}=1 \).
Step4: Solve for y
Substitute \( x = 1 \) into \( y = 4x \), we get \( y = 4\times1 = 4 \).
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The solution of the system is \( x = 1 \), \( y = 4 \)