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Question
find $\frac{d}{dx}(5x - 8)$. $\frac{d}{dx}(5x - 8)=square$
Step1: Apply sum - difference rule
$\frac{d}{dx}(5x - 8)=\frac{d}{dx}(5x)-\frac{d}{dx}(8)$
Step2: Use constant - multiple rule
$\frac{d}{dx}(5x)=5\frac{d}{dx}(x)$ and $\frac{d}{dx}(8) = 0$ (derivative of a constant is 0)
Step3: Recall derivative of $x$
Since $\frac{d}{dx}(x)=1$, then $5\frac{d}{dx}(x)=5\times1 = 5$
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$5$