Question

$\frac{-2x}{\square} < \frac{\square}{\square}$
$x > \square$

Explanation:

Step1: Assume inequality right-hand side

Let the right-hand side be $\frac{6}{-2}$ (a common example for this form).

Step2: Divide both sides by -2

When dividing by a negative number, reverse the inequality sign.
$\frac{-2x}{-2} > \frac{6}{-2}$

Step3: Simplify both sides

Calculate the simplified expressions.
$x > -3$

Answer:

Fill the boxes as follows: bottom left box: $\boldsymbol{-2}$, top right box: $\boldsymbol{6}$, bottom right box: $\boldsymbol{-3}$, final result box: $\boldsymbol{-3}$

(Note: This uses a common constant 6 for the right-hand side numerator; any constant works, but this is a standard example for solving linear inequalities with negative coefficients.)