Question

(\frac{3b^2 + 18b}{b + 6}cdot\frac{1}{b + 8})

Explanation:

Step1: Factor the numerator

Factor \(3b^2 + 18b\) to get \(3b(b + 6)\). So the first fraction becomes \(\frac{3b(b + 6)}{b + 6}\).

Step2: Simplify the first fraction

Cancel out the common factor \(b + 6\) (assuming \(b
eq - 6\)) in the first fraction, we get \(3b\).

Step3: Multiply the simplified fraction with the second fraction

Now we have \(3b\times\frac{1}{b + 8}\).

Step4: Write the final product

The result of the multiplication is \(\frac{3b}{b + 8}\) (with the condition \(b
eq - 6\) and \(b
eq - 8\) to avoid division by zero).

Answer:

\(\frac{3b}{b + 8}\) (where \(b
eq - 6\) and \(b
eq - 8\))