Question

$\frac{dy}{dt}=\tan(15^{circ})(15 km/hr)approx4.30 km/h$

Explanation:

Step1: Recall tangent value

We know that $\tan(15^{\circ}) = 2 - \sqrt{3}\approx0.268$.

Step2: Calculate the product

Multiply $\tan(15^{\circ})\approx0.268$ by $15$ km/hr. So, $0.268\times15 = 4.02$ km/hr.

Answer:

$4.02$ km/hr