Question

$\frac{uv^{-2}}{2u^{-1}v^{-2}}$

Explanation:

Step1: Separate variable terms

$\frac{u}{2u^{-1}} \cdot \frac{v^{-2}}{v^{-2}}$

Step2: Simplify $u$-terms (add exponents)

$\frac{u^{1 - (-1)}}{2} = \frac{u^2}{2}$

Step3: Simplify $v$-terms (add exponents)

$v^{-2 - (-2)} = v^0 = 1$

Step4: Multiply the results

$\frac{u^2}{2} \cdot 1$

Answer:

$\frac{u^2}{2}$