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Question
part 3 of 3 (c) $-25^{\frac{1}{2}} = \square$
Step1: Rewrite exponent as root
Recall $a^{\frac{1}{2}} = \sqrt{a}$, so $-25^{\frac{1}{2}} = -\sqrt{25}$
Step2: Evaluate the square root
$\sqrt{25} = 5$, so $-\sqrt{25} = -5$
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$\boldsymbol{-5}$ (using the $\sqrt{\square}$ template, input $25$ and apply the negative sign outside, resulting in $-5$)