QUESTION IMAGE
Question
solve $-2(x + 5) \geq -6$.
a) $x \leq -2$
b) $x \geq -2$
c) $x \leq 8$
d) $x \geq 8$
Step1: Expand left-hand side
$-2(x + 5) = -2x - 10$
Inequality becomes: $-2x - 10 \geq -6$
Step2: Isolate variable term
Add 10 to both sides:
$-2x - 10 + 10 \geq -6 + 10$
$-2x \geq 4$
Step3: Solve for x, reverse inequality
Divide by -2 (reverse inequality sign):
$\frac{-2x}{-2} \leq \frac{4}{-2}$
$x \leq -2$
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A) $x \leq -2$