Question

solve $4x + 8y = 16$ for $x$.\
\
\\(\bigcirc\\) a. $x = -2y + 16$\
\\(\bigcirc\\) b. $x = -8y + 4$\
\\(\bigcirc\\) c. $x = 8y + 16$\
\\(\bigcirc\\) d. $x = -2y + 4$

Explanation:

Step1: Isolate the x-term

Subtract $8y$ from both sides:
$4x + 8y - 8y = 16 - 8y$
Simplify to get: $4x = 16 - 8y$

Step2: Solve for x

Divide all terms by 4:
$\frac{4x}{4} = \frac{16}{4} - \frac{8y}{4}$
Simplify to get: $x = 4 - 2y$ or $x = -2y + 4$

Answer:

D. $x = -2y + 4$