Question

solve for n.
$-\frac{1}{6} = n - \frac{2}{3}$
$n = \square$

Explanation:

Step1: Add $\frac{2}{3}$ to both sides

To isolate \( n \), we add \(\frac{2}{3}\) to both sides of the equation \(-\frac{1}{6}=n - \frac{2}{3}\). So we have \( n=-\frac{1}{6}+\frac{2}{3} \).

Step2: Find a common denominator

The common denominator of 6 and 3 is 6. Rewrite \(\frac{2}{3}\) with denominator 6: \(\frac{2}{3}=\frac{4}{6}\). Then the equation becomes \( n = -\frac{1}{6}+\frac{4}{6} \).

Step3: Add the fractions

Add the numerators: \( -\frac{1}{6}+\frac{4}{6}=\frac{- 1 + 4}{6}=\frac{3}{6} \). Simplify \(\frac{3}{6}\) to \(\frac{1}{2}\).

Answer:

\(\frac{1}{2}\)