Question

solve for x, 4(x + 1) ≤ 8

Explanation:

Step1: Divide both sides by 4

$\frac{4(z+1)}{4} \leq \frac{8}{4}$
Simplifies to: $z+1 \leq 2$

Step2: Subtract 1 from both sides

$z+1-1 \leq 2-1$
Simplifies to: $z \leq 1$

Answer:

$z \leq 1$