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solve for x. $log_{2}(3x - 5)=3$ $x = $

Question

solve for x. $log_{2}(3x - 5)=3$ $x = $

Explanation:

Step1: Convert log to exponential form

Recall $\log_b(a)=c \iff b^c=a$. So:
$$2^3 = 3x - 5$$

Step2: Calculate $2^3$

$$8 = 3x - 5$$

Step3: Isolate the term with $x$

Add 5 to both sides:
$$8 + 5 = 3x$$
$$13 = 3x$$

Step4: Solve for $x$

Divide both sides by 3:
$$x = \frac{13}{3}$$

Answer:

$\frac{13}{3}$