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solve $|x + 6| = 8$ a. $x = 2$ and $x = -14$ b. $x = -2$ and $x = 14$ c…

Question

solve $|x + 6| = 8$
a. $x = 2$ and $x = -14$
b. $x = -2$ and $x = 14$
c. $x = 2$ and $x = -2$
d. $x = -2$ and $x = -14$

Explanation:

Step1: Split absolute value equation

For $|x+6|=8$, we get two cases:
$x+6=8$ or $x+6=-8$

Step2: Solve first case

Isolate $x$ by subtracting 6.
$x=8-6=2$

Step3: Solve second case

Isolate $x$ by subtracting 6.
$x=-8-6=-14$

Answer:

A. $x = 2$ and $x = -14$