Question

$\sqrt{3x - 3} - 6 = 0$

Explanation:

Step1: Isolate the square root

$\sqrt{3x-3} = 6$

Step2: Square both sides

$(\sqrt{3x-3})^2 = 6^2$
$3x - 3 = 36$

Step3: Solve for x

$3x = 36 + 3$
$3x = 39$
$x = \frac{39}{3}$

Answer:

$x = 13$