Question

② $sqrt3{48m^{7}n^{7}}$ $2m^{2}n^{2}sqrt3{6mn}$ $sqrt3{8m^{7}cdot 6n^{7}}$

Explanation:

Step1: Rewrite radicands as factors

$\frac{\sqrt[3]{8m^6n^6 \cdot 6mn}}{\sqrt[3]{8m^6n^6 \cdot 6mn}}$

Step2: Simplify cube roots

$\frac{\sqrt[3]{8m^6n^6} \cdot \sqrt[3]{6mn}}{\sqrt[3]{8m^6n^6} \cdot \sqrt[3]{6mn}}$

Step3: Cancel common terms

$\frac{2m^2n^2\sqrt[3]{6mn}}{2m^2n^2\sqrt[3]{6mn}} = 1$

Answer:

$1$