Question

subtract.
$(2y^{2} + 2y + 9) - (2y^{2} + 6)$

Explanation:

Step1: Remove parentheses

To subtract the two polynomials, we first remove the parentheses. When we remove the parentheses from the second polynomial, we have to distribute the negative sign to each term inside. So we get:
\(2y^{2}+2y + 9-2y^{2}-6\)

Step2: Combine like terms

Next, we combine the like terms. The \(2y^{2}\) and \(- 2y^{2}\) are like terms, and \(9\) and \(-6\) are like terms.
For the \(y^{2}\) terms: \(2y^{2}-2y^{2}=0\)
For the constant terms: \(9 - 6=3\)
The \(2y\) term remains as it is since there is no other like term to combine with.
Putting it all together, we have \(0 + 2y+3=2y + 3\)

Answer:

\(2y + 3\)