Question

subtract.
$(8d^{2} + d + 9) - (2d^{2} - 2d - 8)$

Explanation:

Step1: Distribute the negative sign

To subtract the second polynomial from the first, we first distribute the negative sign to each term in the second polynomial. This gives us:
\(8d^2 + d + 9 - 2d^2 + 2d + 8\)

Step2: Combine like terms for \(d^2\) terms

The \(d^2\) terms are \(8d^2\) and \(-2d^2\). Combining them, we have:
\(8d^2 - 2d^2 = 6d^2\)

Step3: Combine like terms for \(d\) terms

The \(d\) terms are \(d\) and \(2d\). Combining them, we get:
\(d + 2d = 3d\)

Step4: Combine like terms for constant terms

The constant terms are \(9\) and \(8\). Combining them, we obtain:
\(9 + 8 = 17\)

Step5: Combine all the results

Putting together the results from the previous steps, we have:
\(6d^2 + 3d + 17\)

Answer:

\(6d^2 + 3d + 17\)