Question

subtract:
$(8x^3 - 4x + 6) - (3x^2 - 7x + 9)$

Explanation:

Step1: Distribute the negative sign

We need to distribute the negative sign to the second polynomial. So, \((8x^{3}-4x + 6)-(3x^{2}-7x + 9)=8x^{3}-4x + 6-3x^{2}+7x - 9\)

Step2: Combine like terms

• For the \(x\) terms: \(-4x+7x = 3x\)
• For the constant terms: \(6 - 9=-3\)
• The \(8x^{3}\) and \(-3x^{2}\) terms remain as they are since there are no like terms.

Putting it all together, we get \(8x^{3}-3x^{2}+3x - 3\)

Answer:

\(8x^{3}-3x^{2}+3x - 3\)