Question

1. megan had 50¢. she lost 1 nickel. circle the 5 coins that show how much she has left. 4. yoshi had 55¢. he gave his sister a dime. circle the 3 coins that show how much he has left. 5. k

Explanation:

Problem 3: Megan's Coins

Step1: Calculate remaining cents

Megan had 50¢, lost 1 nickel (5¢). So remaining: $50 - 5 = 45$¢.

Step2: Identify coin values

• Nickel: 5¢, Dime: 10¢, Quarter: 25¢, Penny: 1¢.
• We need 5 coins summing to 45¢. Let's check: 1 quarter (25¢) + 2 dimes (10¢×2 = 20¢) = 45¢? No, that's 3 coins. Wait, maybe 1 quarter (25¢), 1 dime (10¢), 3 nickels? No, 25 + 10 + (5×3)=25+10+15=50. Wait, original Megan had 50¢, lost 5¢ (nickel), so 45¢. Let's see the coins: 1 quarter (25¢), 4 dimes? No, 25 + (10×4)=65. Wait, the coins shown: 2 quarters? No, in problem 3, coins are: 2 quarters? Wait no, the first coin is a quarter? Wait, the first coin (left) in problem 3: maybe a quarter (25¢), then four dimes? No, 25 + (10×4)=65. Wait, no, Megan had 50¢, lost 5¢, so 45¢. Let's count the coins: 1 quarter (25¢), 2 dimes (20¢), 2 nickels (10¢)? 25+20+10=55. No. Wait, maybe the coins are: 1 quarter (25¢), 1 dime (10¢), 3 nickels? 25+10+15=50. No. Wait, maybe I misread. Wait, the problem says "circle the 5 coins that show how much she has left". Let's re-express: 45¢ with 5 coins. 45¢ can be 1 quarter (25¢) + 2 dimes (10×2=20) + 0 nickels + 0 pennies? No, that's 3 coins. Wait, maybe the coins are: 4 dimes (40¢) and 1 nickel (5¢): 40+5=45¢. Yes! 4 dimes (10×4=40) and 1 nickel (5) is 45, with 5 coins. So circle 4 dimes and 1 nickel? Wait, looking at the coins in problem 3: the coins are: 1 quarter (25¢), 4 dimes (10¢ each), and 1 nickel (5¢)? Wait, no, the first coin (top left) is a quarter? Then below it another quarter? No, the first coin (left) in problem 3: maybe a quarter (25¢), then four dimes (10¢ each), and one nickel (5¢). Wait, Megan had 50¢, lost 5¢ (nickel), so 45¢. So 4 dimes (40¢) and 1 nickel (5¢) sum to 45¢, which is 5 coins. So circle those 4 dimes and 1 nickel? Wait, the coins shown: let's count the coins in problem 3: 2 quarters? No, the first coin (top left) is a quarter (25¢), then four dimes (10¢ each), and one nickel (5¢). Wait, 25 + (10×4) +5=25+40+5=70. No. I think I made a mistake. Wait, Megan had 50¢, lost 1 nickel (5¢), so 45¢. 45¢ with 5 coins: 9 nickels? No, 5 nickels is 25¢. Wait, 4 dimes (40¢) and 1 nickel (5¢): 4+1=5 coins, 40+5=45. Yes. So the coins: the four dimes (the four coins with the head, maybe dimes) and one nickel (the dark coin, maybe nickel). So circle those 5 coins: 4 dimes and 1 nickel.

Step3: Final check

4 dimes (10×4=40) + 1 nickel (5) = 45¢, which is 50 - 5 = 45. Correct.

Step1: Calculate remaining cents

Yoshi had 55¢, gave a dime (10¢). Remaining: $55 - 10 = 45$¢? Wait, no: 55 - 10 = 45? Wait, 55 - 10 = 45? No, 55 - 10 = 45? Wait, 55 minus 10 is 45? Wait, 55 - 10 = 45? Yes. Wait, no: 55 - 10 = 45? Wait, 50 + 5 is 55, minus 10 is 45? Wait, no, 55 - 10 = 45? Wait, 55 - 10 = 45. Wait, but let's check again: Yoshi had 55¢, gave a dime (10¢), so 55 - 10 = 45¢. Now, circle 3 coins that sum to 45¢.

Step2: Identify coin values

Coins shown: 1 quarter (25¢), 4 dimes (10¢ each), 1 nickel (5¢), 1 penny? No, the dark coin is a penny? No, the dark coin (right) is a penny? No, maybe a nickel? Wait, the coins: top left: quarter (25¢), top right: dime (10¢), middle right: penny? No, middle right: dark coin, maybe a penny (1¢), but 25 + 10 + 10 = 45? 25 + 10 + 10 = 45? Yes! 25 (quarter) + 10 (dime) + 10 (dime) = 45¢. So three coins: 1 quarter, 2 dimes. Let's check the coins: the quarter (top left), two of the dimes (e.g., top right, middle right, or bottom ones). So circle the quarter and two dimes.

Answer:

(for problem 3): Circle 4 dimes and 1 nickel (or the 5 coins that sum to 45¢, likely 4 dimes and 1 nickel).

Problem 4: Yoshi's Coins