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the midpoint of ab is m(-2,4). if the coordinates of a are (-1,5), what…

Question

the midpoint of ab is m(-2,4). if the coordinates of a are (-1,5), what are the coordinates of b? answer attempt 2 out of 2

Explanation:

Step1: Recall mid - point formula

The mid - point formula for two points $A(x_1,y_1)$ and $B(x_2,y_2)$ is $M(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$. Here $x_1=-1,y_1 = 5$ and $M(-2,4)$.

Step2: Solve for $x_2$

We know that $\frac{x_1 + x_2}{2}=-2$. Substitute $x_1=-1$ into it: $\frac{-1 + x_2}{2}=-2$. Multiply both sides by 2: $-1+x_2=-4$. Then add 1 to both sides: $x_2=-4 + 1=-3$.

Step3: Solve for $y_2$

We know that $\frac{y_1 + y_2}{2}=4$. Substitute $y_1 = 5$ into it: $\frac{5 + y_2}{2}=4$. Multiply both sides by 2: $5+y_2 = 8$. Then subtract 5 from both sides: $y_2=8 - 5 = 3$.

Answer:

$(-3,3)$